Question

How do you solve `8-5(x+3)=2`?

Answer 1

Expand the bracket

`8-5x-15=2`

collect like terms

`-5x-7=2`

add `5x`

`-7=2+5x`

subtract 2

`-9=5x`

divide by 5

`-9/5=x`

Answer 2

`x=-9/5`

Explanation:

`"distribute bracket and simplify"`

`8-5x-15=2`

`-5x-7=2`

`"add 7 to both sides"`

`-5x=2+7=9`

`"divide both sides by "-5`

`x=9/(-5)=-9/5`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`8-5(-9/5+15/5)=8-(5xx6/5)=8-6=2`

`x=-9/5" is the solution"`

Answer 3

`x = -9/5 = -1.8`

Explanation:

1) Eliminate the brackets: Multiply the `-5` into the bracket.

`-5(x)" "` and `" "-5(3)`

You should get:

`8-5x-15=2`

2) Common Factor: Take the `8` and add it to `-15`.

`-15 + 8`

You should get:

`-5x-7=2`

3) Get the `x` alone: Take the `-7` over to the other side so it turns into a positive:

`-5x=2+7`

`-5x=9`

Then to get the `x` completely alone, you have to divide both sides by `-5` because the opposite of multiplication is division and what you do to one side, you have to do to the other.

You should get:

`x = 9/-5 = -1.8`

Answer 4

`x=-9/5`

Explanation:

Let's start by distributing the `-5` to both of the terms in parenthesis. Doing this, we will get:

`-5x+8-15=2`

Which simplifies to

`-5x-7=2`

Adding `7` to both sides gives us

`-5x=9`

Lastly, dividing both sides by `-5`, we get

`x=-9/5`

Hope this helps!