Question

How do you solve `x^2-8x-1=8` by completing the square?

Answer 1

`x^2-8x-1=8`

`x^2-8x-9=0`

`(x-4)^2-16-9=0`

`(x-4)^2-25=0`

`(x-4)^2=25`

`(x-4)=\pm5`

`x-4=5 or x-4=-5`

`x=9 or x=-1`