Question

How do you find the intercepts for `3x + 4y = -4`?

Answer 1

`"x-intercept "=-4/3," y-intercept "=-1`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr0+4y=-4rArry=-1larrcolor(red)"y-intercept"`

`y=0rArr3x+0=-4rArrx=-4/3larrcolor(red)"x-intercept"`
graph{(y+3/4x+1)((x-0)^2+(y+1)^2-0.04)((x+4/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Answer 2

`x / -(4/3) + y/-1 = 1` is the intercept form of the line.

x-intercept `= (4/3)`, y-intercept `= -1`

Explanation:

Intercept form of equation is `x/a + y/b = 1`

`3x + 4y = -4`

`-(3/4)x - cancel(4/4)y = 1`

`x / -(4/3) + y/-1 =1`

x-intercept `= -(4/3)`, y-intercept `= -1`