How do you solve k^2-6k+8=0k2−6k+8=0 by completing the square?
2 Answers
Jun 16, 2018
Explanation:
"subtract 8 from both sides"subtract 8 from both sides
k^2-6k=-8k2−6k=−8
k^2+2(-3)k color(red)(+9)=-8color(red)(+9)k2+2(−3)k+9=−8+9
(k-3)^2=1(k−3)2=1
color(blue)"take square root of both sides"take square root of both sides
k-3=+-1larrcolor(blue)"note plus or minus"k−3=±1←note plus or minus
k=3+-1k=3±1
k=3-1=2" or "k=3+1=4k=3−1=2 or k=3+1=4
Jun 16, 2018
Explanation:
First lets complete the square: