What is the domain and range of #f(x) = (4x^2 - 4x - 8) / (2x + 2)#?

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Answer 1 · 2018-06-18T08:26:36

The domain is #x in RR#.
The range is #yin RR#

The function is

#f(x)=(4x^2-4x-8)/(2x+2)=(4(x^2-x-2))/(2(x+1))=(2(x-2)cancel(x+1))/(cancel(x+1))#

#=2(x-2)#

This is the equation of a line, #y=2x-4#

The domain is #x in RR#

The range is #yin RR#

graph{(4x^2-4x-8)/(2x+2) [-18.02, 18.02, -9.01, 9.02]}