Question

How do you write `(x^2-9) / ( |x+3| )` as a piecewise function?

Answer 1

`f(x)=x-3` if `x > -3` and `f(x)=-(x-3)` if `x<-3`

Explanation:

Not that

`(x+3)/|x+3|=1` if `x > -3`

`(x+3)/|x+3|=-1` if `x<-3`