What is the derivative of #y=e^((2x)/3)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Sonnhard Jun 18, 2018 #y'=2/3*e^(2/3*x)# Explanation: Using that #(e^x)'=e^x# and the chain rule we get #y'=2/3*e^(2/3x)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 5005 views around the world You can reuse this answer Creative Commons License