Question

How do you differentiate `f(x) = x^3/(xtanx-2)` using the quotient rule?

Answer 1

`f'(x)=(-x^2(6+x^2sec(x)^2-2xtan(x)))/(-2+x*tan(x))^2`

Explanation:

After the Quotient rule we get

`f'(x)=(3x^2(xtan(x)-2)-x^3(tan(x)+xsec^2(x)))/(xtan(x)-2)^2`
which simplifies to the term above.