How do you solve #(x+1)/3 = (2x-1)/4#?
2 Answers
Jun 21, 2018
Explanation:
#"multiply both sides by the lowest common multiple of"#
#"3 and 4 that is 12"#
#cancel(12)^4xx(x+1)/cancel(3)^1=cancel(12)^3xx(2x-1)/cancel(4)^1#
#4(x+1)=3(2x-1)larrcolor(blue)"distribute"#
#4x+4=6x-3#
#"subtract "4x" from both sides"#
#4=2x-3#
#"add 3 to both sides and divide by 2"#
#7=2xrArrx=7/2#
#color(blue)"As a check"#
#"left "=(7/2+2/2)/3=(9/2)/3=9/6=3/2#
#"right "=(14/2-2/2)/4=6/4=3/2#
#x=7/2" is the solution"#
Jun 21, 2018
Explanation:
Multiply both sides by
So, the equation becomes
Expand both sides to get
Subtract
Subtract
Divide both sides by