Question

How do you solve the system : `x-3y=-2`, `4x-2y=-8`?

Answer 1

Here `x=-2&y=0`

Explanation:

we have two equations
let `x-3y=-2` ...............eq( 1)
and `4x-2y=-8`..............eq(2)
Now we have to subsitute or eliminate either x or y
let us eliminate y
now multiply eq(1) with 2 and eq(2) with 3,we will get
`2x-6y=-4`...eq(1) and `12x-6y=-24`....eq(2)
now subtract eq(1) from eq(2)
we will get
`10x=-20` we see that it is in a linear form solving x we get
x=-2
putting y in eq(1) and eq(2)
we get y=0.