How do you factor the expression #x^2+14x+48#?

1 Answer
sjc
Jun 22, 2018

#(x+6)(x+8)#

Explanation:

#x^2+14x+48#

we have two brackets like

#( x + color(white)(_ ))(x +color(white)( _) ) #

the blank spaces will be numbers such that they are factors of the constant #48# that add up to the coefficient of #x#that is #14#

we have #6" & "8#

#x^2+14x+48=(x+6)(x+8)#

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
26714 views around the world
You can reuse this answer
Creative Commons License