How do you find the derivative of (pi/2)sinx-cosx? Calculus Basic Differentiation Rules Summary of Differentiation Rules 1 Answer Alan N. Jun 24, 2018 dy/dx = (pi/2)cosx + sinx Explanation: y = (pi/2)sinx - cosx Since pi/2 is a constant we can apply linearity for the derivative. Hence, dy/dx = (pi/2)d/dx(sinx) - d/dx(cosx) Applying standard derivatives dy/dx = (pi/2)cosx - (-sinx) = (pi/2)cosx + sinx Answer link Related questions What is a summary of Differentiation Rules? What are the first three derivatives of (xcos(x)-sin(x))/(x^2)? How do you find the derivative of (e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))? How do I find the derivative of y= x arctan (2x) - (ln (1+4x^2))/4? How do you find the derivative of y = s/3 + 5s? What is the second derivative of (f * g)(x) if f and g are functions such that f'(x)=g(x)... How do you calculate the derivative for g(t)= 7/sqrtt? Can you use a calculator to differentiate f(x) = 3x^2 + 12? What is the derivative of ln(x)+ 3 ln(x) + 5/7x +(2/x)? How do you find the formula for the derivative of 1/x? See all questions in Summary of Differentiation Rules Impact of this question 6292 views around the world You can reuse this answer Creative Commons License