Question

How do you find the derivative of `(pi/2)sinx-cosx`?

Answer 1

`dy/dx = (pi/2)cosx + sinx`

Explanation:

`y = (pi/2)sinx - cosx`

Since `pi/2` is a constant we can apply linearity for the derivative.

Hence, `dy/dx = (pi/2)d/dx(sinx) - d/dx(cosx)`

Applying standard derivatives

`dy/dx = (pi/2)cosx - (-sinx)`

`= (pi/2)cosx + sinx`