Question

How do you derive `y = 1/(1-x^2)` using the quotient rule?

Answer 1

`y'=2x/(1-x^2)^2`

Explanation:

Writing your function in the form

`y=(1-x^2)^(-1)`
and using the power and chain rule we get

`y'=(-1)(1-x^2)^(-2)(-2x)=(2x)/(1-x^2)^2`