Question

How do you solve the triangle given `triangleABC, a=8, mangleB=35, mangleC=55`?

Answer 1

See below

Explanation:

We know
`a=8`
`hatB=35`
`hatC=55`

Then however `hatA+hatB+hatC=180` then `hatA=90`

ABC is a right triangle

By `sin` theorem `a/sinA=b/sinB` or `8/1=b/sin35` then

`b=8·sin35=4.5886`

And again with leg c: `c/sin55=8/sin90` and `c=8·sin55=6.5532`

Or by Pitagorean theorem `8^2=4.5886^2+c^2`