How do you factor #x^2 + 17x + 42 =0#?

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Answer 1 · 2018-06-26T08:58:49

-3, -14

#x^2 + 17x +42 = 0#
or, #x^2 + 14x + 3x +42 = 0#
or, #x(x + 14) + 3 (x + 14) = 0#
or, #(x + 3)(x+14)# = 0
or, #x= -3, -14#

Answer 2 · 2018-06-26T09:14:46

#(x+3)(x+14)=0#

#"the factors of " +42" which sum to "+17#
#"are "+3" and "+14#

#x^2+17x+42=0#

#(x+3)(x+14)=0#