How do you simplify #-2cd^2(3c^2d-2cd^2+cd^2#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer sankarankalyanam Jun 26, 2018 #color(maroon)(=> 2c^2 d^3 (3c - 2d) = 6c^3d^3 - 4c^2d^4# Explanation: #-2 cd^2 (3 c^2d - 2cd^2 + cd^2)# #=>-2cd^2 (3 c^2d - cd^2)# #=> (2cd^2 * cd ) (3c - 2d)# #color(maroon)(=> 2c^2 d^3 (3c - 2d) = 6c^3d^3 - 4c^2d^4# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 1992 views around the world You can reuse this answer Creative Commons License