How do you solve #abs(2z+2)-1>3#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Shwetank Mauria Jun 26, 2018 #z>1# or #z<-3# Explanation: If #|2z+2|-1>3#, then either we have #|2z+2|=2z+2#, in which case #|2z+2|-1>3# becomes #2z+2-1>3# or #2z>2# i.e. #z>1# or #|2z+2|=-2z-2# (in case it is negative) and we have #-2z-2-1>3# or #-2z>6# i.e. #z<-3# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1504 views around the world You can reuse this answer Creative Commons License