Question

What is the derivative of tan(sin x)?

Answer 1

`d/dx[tan(sinx)]=sec^2(sinx)cosx`

Explanation:

The chain rule for derivatives is
`y=f(g(x))->dy/dx=f'(g(x))g'(x)`
With `f(x)=tanx` and `g(x)=sinx`, we get `d/dx[tan(sinx)]=sec^2(sinx)cosx`

Answer 2

a