How do you solve #a-3b=2 # and #2a+4b=9#?

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Answer 1 · 2018-07-02T09:08:54

#color(green)(a = 7/2, b = 1/2#

#a - 3b = 2, " Eqn (1)"#

#2a + 4b = 9, " Eqn (2)"#

#"Eqn (2) "- 2 * " Eqn (1) is "#

#cancel(2a) + 4b - cancel(2a) + 6b = 9 - 4#

# 10 b = 5 " or " b = 1/2#

#a - (3 * (1/2)) = 2#

#a = 2 + 3/2 = 7/2#