What is #81 / (9^2 - 72) - (5-3)#?

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Answer 1 · 2018-07-03T01:27:59

#7#

Here's how I did it:

#81/(9^2-72)-(5-3)#

#=81/(81-72)-2#

#=81/9-2#

#=9-2#

#=7#

Answer 2 · 2018-07-03T03:45:49

#7#

The denominator simplifies to #81-72#, and we're now left with

#81/9-(5-3)#

This further simplifies to

#9-(5-3)#

#9-2=7#

Hope this helps!