How do you solve #4e^x=91#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Somebody N. Jul 3, 2018 #color(blue)(x=ln(91/4)~~3.124565145# Explanation: #4e^x=91# divide by 4: #e^x=91/4# Taking natural logarithms of both sides: #xln(e)=ln(91/4)# #ln(e)=1# #:.# #x=ln(91/4)~~3.124565145# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 4424 views around the world You can reuse this answer Creative Commons License