How do you graph $y=-2sinθ$ ?

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Answer 1 · 2018-07-04T01:42:27

As below.

Standard form of a sine function is $y = A sin(Bx - C) + D$

$"Given : " y = -2 sin theta$

$A = -2, B = 1, C = D = 0$

$Amplitude = |A| = |-2| = 2$

$"Period " = (2pi) / |B| = 2pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift or Midline " = D = 0$

graph{-2 sin x [-10, 10, -5, 5]}

How do you graph y=-2sinθy=-2sinθ?