How do you graph #x^2 + y^2 = 16#?
2 Answers
Mar 13, 2018
This is a circle of radius
Explanation:
Given:
#x^2+y^2=16#
Note that we can rewrite this equation as:
#(x-0)^2+(y-0)^2 = 4^2#
This is in the standard form:
#(x-h)^2+(y-k)^2 = r^2#
of a circle with centre
So this is a circle of radius
graph{x^2+y^2 = 16 [-10, 10, -5, 5]}
Jul 7, 2018
See below:
Explanation:
The equation of a circle is given by
With center
We have no
We know from
graph{x^2+y^2=16 [-10, 10, -5, 5]}
Hope this helps!