How do you solve #8(k+2)=1#?

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Answer 1 · 2018-07-07T06:57:28

#k=-15/8#

Dividing the whole equation by #8# we get

#k+2=1/8#

subtracting #1#

#k=1/8-2=1/8-16/8=-15/8#

Answer 2 · 2018-07-07T07:38:57

#k=-15/8#

#"divide both sides by 8"#

#k+2=1/8#

#"subtract 2 from both sides"#

#k=1/8-2=1/8-16/8=-15/8#

Answer 3 · 2018-07-08T16:48:51

#k=-15/8#

Let's divide both sides by #8# to begin isolating the #k# term. We get

#k+2=1/8#

We can next subtract #2# from both sides to get

#k=1/8-16/8=-15/8#

Thus, #k=-15/8#

Hope this helps!