How do you simplify and write #(4x^-4y^2)^-3# with positive exponents?

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Answer 1 · 2018-07-10T00:16:17

#x^12/(64y^6)#

Our expression is the same as

#1/(4x^-4y^2)^3#

#4^3=color(blue)(64)#, #(x^-4)^3=x^(-4*3)=color(blue)(x^(-12))#, #(y^2)^3-y^(2*3)=color(blue)(y^6)#

With this in mind, we now have the following:

#1/(64x^-12y^6)#

We can make the negative exponent positive by bringing it to the numerator. We now have

#x^12/(64y^6)#

Hope this helps!