How deep is the water in the trough if a water trough is in the shape of a rectangular prism that is 12 feet long by 3 feet wide and has 9.4 cubic feet of water?

2 Answers
Jul 11, 2018

The depth of the trough is "0.2611 ft"0.2611 ft or "3.1332 in"3.1332 in.

Explanation:

"Volume"="length"xx"width"xx"height"Volume=length×width×height

To calculate height (depth), divide the given volume by the product of the length and width.

"height"=(9.4"ft"^3)/(12"ft"xx"3ft")height=9.4ft312ft×3ft

"height"=(9.4"ft"^3)/(36"ft"^2)="0.2611 ft"height=9.4ft336ft2=0.2611 ft

Convert feet to inches.

0.2611color(red)cancel(color(black)("ft"))xx("12 in")/(1color(red)cancel(color(black)("ft")))="3.1332 inches"

Jul 11, 2018

0.26 ft

Explanation:

A rectangular prism is a 3D shape with 6 faces, where each face is a rectangle.
A rectangle has 4 sides where all 4 corners are right angles (a square is a rectangle with all sides the same length).

The volume of a rectangular prism is length * width * height

V = L * W * H

So the volume of water in the trough is

V_"trough" = 12 * 3 * H cubic feet

If V_"trough" = 9.4 cubic feet then

9.4 = 12 * 3 * H

9.4/ (12 * 3)= H

H= 9.4/ 36

H= 9.4/ 36

= 0.26 ft