How to determine a temperature on which process is spontaneous by using function of Gibbs free energy?

Seems like this question can't be solved, maybe I just need any correlation between temperature and gibbs free energy?

1 Answer
Jul 11, 2018

If Delta S>0
(Delta H) / (Delta S) < T
If Delta S<0
(Delta H) / (Delta S) > T

Explanation:

Delta G = Delta H - T Delta S
G is gibbs free energy
H is enthalpy
S is entropy
Delta G = - T Delta S_"net"
If Delta S_"net" < 0
DeltaG = - T Delta S_"net"<0(because T>0K), the process is spontaneous.

If Delta H and Delta S is given,
Delta H - T Delta S<0
Delta H < T Delta S
If Delta S>0
(Delta H) / (Delta S) < T
If Delta S<0
(Delta H) / (Delta S) > T