Question

How do you solve this system of equations: `3x = 16+ 2y ; 5y = - 2x - 2`?

Answer 1

`x=4,y=-2`

Explanation:

From the second equation we get

`y=1/5(-2x-2)`
plugging this (for `y`) in the first equation

`3x=16+2(1/5(-2x-2))`
`3x=16+2/5(-2x-2)`
multiplying by `5`
`15x=80-4x-4`
so we get

`19x=76`
`x=4`

and

`y=1/5*(-8-2)=-10/5=-2`