How do you factor #2y^2+7y+5#?

2 Answers
Jul 12, 2018

#(2y+5)(y+1)#

#2y^2# only has #y# and #2y# as factors

Similarly 5 only has factors 1 and 5

Jul 12, 2018

#2y^2+7y+5=color(blue)((2y+5)+(y+1)#

Explanation:

Factor:

#2y^2+7y+5#

Use the #"ac"# method to factor this trinomial. #a=2# and #c=5#

Multiply #2# by #5# to get #10#. Find two numbers that when added equal #7# and when multiplied equal #10#. The numbers #5# and #2# meet the requirements.

Split the middle term #7y# to #5y+2y#. This method is also sometimes called "splitting the middle term."

#2y^2+5y+2y+5#

Factor out common terms in the first two and second two terms.

#y(2y+5)+(2y+5)# #larr# understood to be #1(2y+5)#

Factor out the common term #(2y+5)#.

#(2y+5)+(y+1)#