How do you find the inverse of #y = -logx#?

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Answer 1 · 2018-07-13T14:38:08

#y=e^{-x}#

Given function:

#y=-\log x#

#\log x=-y#

#x=e^{-y}#

Now, interchanging #y# & #x# we get

#y=e^{-x}#

Thus, #y=e^{-x}# is inverse of given function #y=-\log x#