How do you find the derivative of #n(t) = 150 - 600/root3(16+3t^2)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Sonnhard Jul 13, 2018 #n'(t)=1200t/(root(3)(16+3t^2)^2# Explanation: writing #n(t)=150-600(16+3t^2)^(-1/3)# note that #(150)'=0# and #n'(t)=-600*(-1/3)(16+3t^2)^(-2/3)6t# simplifying we obtain #n'(t)=1200t/root(3)(16+3t^2)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1564 views around the world You can reuse this answer Creative Commons License