How do you find the roots, real and imaginary, of #y= 2x^2 - 2x - (x-9)^2 # using the quadratic formula?

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Answer 1 · 2018-07-14T20:17:19

#x=-8pmsqrt(145)#

Simplifying the given equation and using the Formula
#(a-b)^2=a^2-2ab+b^2#

we get
#2x^2-2x-(x^2-18x+81)=0# combinging like Terms

#x^2+16x-81=0#

#x^2+px+q=0#

#x_(1,2)=-p/2pmsqrt((p/2)^2-q)#

we get

#x_(1,2)=-8pmsqrt(64+81)#

#x_(1,2)=-8pmsqrt(145)#