Question

How do you solve `2\cdot 3^ { 10x + 6} = 18`?

Answer 1

The solution is `=-2/5`

Explanation:

The equation is

`2*3^(10x+6)=18`

Dividing by `2`

`3^(10x+6)=18/2=9=3^2`

Therefore,

The exponents are equal

`10x+6=2`

`10x=2-6=-4`

Dividing by `10`

`x=-4/10=-2/5`

Answer 2

`x=-2/5`

Explanation:

`3^(10x+6)=9`

`log_(3)3^(10x+6)=log_(3)9`

`10x+6=2`

`10x=-4`

`x=-4/10`

`x=-2/5`

Answer 3

`x=-2/5`

Explanation:

Here ,

`2*3^(10x+6)=2*9`

`=>2*3^(10x+6)=2*3^2`

Dividing both sides by `2`

`(cancel2*3^(10x+6))/cancel2=(cancel2*3^2)/cancel2`

`=>3^(10x+6)=3^2`

`=>10x+6=2`

Adding both sides `(-6)`

`=>10x+6+(-6)=2+(-6)`

`=>10x=-4`

Dividing both sides by `10`

`=>x=-4/10=-(2xx2)/(2xx5)`

`=>x=-2/5`

Answer 4

`x=-0.4`

Explanation:

`2\cdot 3^{10x+6}=18`

`3^{10x+6}=18/2`

`3^{10x+6}=9`

`3^{10x+6}=3^2`

Comparing the powers on base `3` on both the sides we get

`10x+6=2`

`10x=2-6`

`10=-4`

`x=-4/10`

`x=-0.4`