How do you solve #-1/2(b+2)+3b=-1#?

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Answer 1 · 2018-07-21T23:37:28

Work backwards combine like terms and solve.

The opposite of PEMDAS is PESADM
Start with parenthesis ( P there are no exponents E)

# -1/2 ( b +2) + 3b = -1 ;- 1/2 xx b + -1/2 xx 2 + 3b = -1#
b -1
This is the result of the distributive property

#-1/2b + -1/2 xx 2 + 3b = -1:= -1/2b + -1 +3b = -1#

Using the communicative property to combine like terms gives

#-1/2b + 3b -1 = -1#

Combing like terms gives.

# 2 1/2 -1 = -1 #

Adding + 1 to both sides gives.

# 2 1/2b -1 + 1 = -1 +1 #

The result is

# 2 1/2b = 0 #

dividing both sides by 2 1/2 gives

#(2 1/2 b}/ ( 2 1/2) = 0 /( 2 1/2) #

The answer is

# b = 0 #

Answer 2 · 2018-07-21T23:47:57

#b=0#

Let's distribute the #-1/2# to both terms to get

#-1/2b-1+3b=-1#

We can combine like terms on the left to get

#2.5b-1=-1#

Adding #1# to both sides gives us

#2/5b=0#

Dividing both sides by #2.5#, we get

#b=0#

Hope this helps!