Question

How do you find the exact values of the six trig functions of angle 120?

Answer 1

See values of all six trig. functions below

Explanation:

`\sin120^\circ=\sin(180^\circ-60^circ)=\sin60^\circ=\sqrt3/2`

`\cos120^\circ=\cos(180^\circ-60^circ)=-\cos60^\circ=-1/2`

`\tan120^\circ=\tan(180^\circ-60^circ)=-\tan60^\circ=-\sqrt3`

`\cosec120^\circ=\cosec(180^\circ-60^circ)=\cosec 60^\circ=2/\sqrt3`

`\sec120^\circ=\sec(180^\circ-60^circ)=-\sec 60^\circ=-2`

`\cot120^\circ=\cot(180^\circ-60^circ)=-\cot60^\circ=-1/\sqrt3`