The power P of work on the block of mass m=1400\ kg moving with a constant velocity v=1\ m/s up the plane inclined at an angle \theta=\tan^{-1}(3/4) is given as
P=\text{total force acting on the block down the plane}\times \text{velocity}
P=(mg\sin\theta+\mu mg\cos\theta) v
=mg(\sin\theta+mu\cos\theta)v
=(1400)(9.81)(3/5+(0.4) 4/5)\cdot 1
=12635.28 \ W
=12.635\ kW