The power #P# of work on the block of mass #m=1400\ kg# moving with a constant velocity #v=1\ m/s# up the plane inclined at an angle #\theta=\tan^{-1}(3/4)# is given as
#P=\text{total force acting on the block down the plane}\times \text{velocity}#
#P=(mg\sin\theta+\mu mg\cos\theta) v#
#=mg(\sin\theta+mu\cos\theta)v#
#=(1400)(9.81)(3/5+(0.4) 4/5)\cdot 1#
#=12635.28 \ W#
#=12.635\ kW#