Question

How do you graph `f(x) = 4 sin(x - pi/2 ) + 1`?

Answer 1

As below.

Explanation:

Standard form of sine function is `f(x) = A sin (Bx - C) + D`

Given `f(x) = 4 sin (x - pi/2) + 1`

`A = 4, B = 1, C = pi/2, D = 1`

#Amplitude = |A| = 4,

Period `= (2pi) / |B| = (2pi)/1 = 2pi`

Phase Shift `= -C / B = -(pi/2) / (1) = -pi/2, color(brown)(pi/2` to the LEFT.

Vertical Shift `D = 1`

graph{4 sin(x - pi/2) + 1 [-10, 10, -5, 5]}