Question

How do you find `abs( 7-5i )`?

Answer 1

`sqrt74`

Explanation:

`"given a complex number "z=x+yi" then"`

`"it's magnitude is"`

`|z|=|x+yi|=sqrt(x^2+y^2)`

`"here "x=7" and "y=-5`

`|7-5i|=sqrt(7^2+(-5)^2)=sqrt74`

Answer 2

`\sqrt{74}`

Explanation:

The absolute value of any complex number `(a+ib)` is given as

`|a+ib|=\sqrt{a^2+b^2}`

`\therefore |7-5i|`

`=\sqrt{7^2+(-5)^2}`

`=\sqrt{74}`