How do you find abs( 7-5i )?

2 Answers
Jul 28, 2018

sqrt74

Explanation:

"given a complex number "z=x+yi" then"

"it's magnitude is"

|z|=|x+yi|=sqrt(x^2+y^2)

"here "x=7" and "y=-5

|7-5i|=sqrt(7^2+(-5)^2)=sqrt74

\sqrt{74}

Explanation:

The absolute value of any complex number (a+ib) is given as

|a+ib|=\sqrt{a^2+b^2}

\therefore |7-5i|

=\sqrt{7^2+(-5)^2}

=\sqrt{74}