How do you solve the system #3x + 4y =2# and #2x + 3y =1#?

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Answer 1 · 2018-07-30T13:51:12

#color(green)(x = 2, y = -1#

#3x + 4y = 2#, Eqn (1)

#2x + 3y = 1#, Eqn (2)

#6x + 8y = 4, Eqn (1) * 2#

#6x + 9y = 3, Eqn (2) * 3#

Subtracting one from the other,

#6x + 8y - 6x - 9y = 4 - 3#

#-y = 1# or #y = -1#

Substituting value of y in Eqn (1),

#3x + 4*-1 = 2#

#3x - 4 = 2#

#3x = 4 + 2 = 6#

#x = 6 / 3 = 2#