Question

How do you graph `f(x) = 4 cos(x - pi/2 )`?

Answer 1

See a sine wave and details.

Explanation:

`y = 4 cos ( x - pi/2 ) = 4 cos ( pi/2 - x )`

`=4 sin x in 4 [ - 1, 1 ] = [ - 4, 4 ]`

The amplitude of this sine wave is 4 and the period is `2 pi`.

See wave, for one period, `x in [ - pi, pi ]`:
graph{(y - 4 sin x)(y^2-16)(x^2-(pi)^2)=0[-6.4 6.4 -4.2 4.2]}