What is complex conjugate of #2 - sqrt(2i)#?
1 Answer
Jul 31, 2018
Explanation:
#"Given a complex number "z=x+-yi#
#"then the complex conjugate is "x color(red)(∓)i#
#"note that the real part remains unchanged while the sign"#
#"of the imaginary part reverses"#
#"conjugate of "2-sqrt2i" is "2color(red)(+)sqrt2i#
