How do you solve the polynomial #24x^2-4x=0#?

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Answer 1 · 2018-07-31T19:28:33

#x=0 or x=1/6#

Here,

#p(x)=24x^2-4x and x=0#

#=>p(0)=24(0)-4(0)=0#

So, factoring we get

#24x^2-4x=0#

#:.4x(6x-1)=0#

#:.4x=0 or 6x-1=0#

#:.x=0 or 6x=1#

#:.x=0 or x=1/6#