How do you evaluate #(8+ \sqrt { 3^ { 2} + 2\cdot 3+ 1})/-4#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Shantelle Aug 4, 2018 #-3# Explanation: #(8 + sqrt(3^2 + 2 * 3 + 1))/-4# #=(8 + sqrt(9 + 6 + 1))/-4# #=(8 + sqrt(16))/-4# #=(8+4)/-4# #=12/-4# #=-3# Hope this helps! Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1712 views around the world You can reuse this answer Creative Commons License