Question

How do you solve `10x^2 - 19x + 6 = 0` using the quadratic formula?

Answer 1

`x = (19 + 2sqrt19)/20` and `x = (19 - 2sqrt19)/20`

Explanation:

`10x^2 - 19x + 6 = 0`

The quadratic formula is `x = (-b +- sqrt(b^2 - 4ac))/(2a)`.

We know that: `a = 10`, `b = -19`, and `c = 6` based on the equation, so let's plug them into the formula:
`x = (-(-19) +- sqrt((-19)^2 - 4(10)(6)))/(2(10))`

`x = (19 +- sqrt(361 - 240))/20`

`x = (19 +- sqrt76)/20`

`x = (19 +- sqrt(4*19))/20`

`x = (19 +- 2sqrt19)/20`

Hope this helps!