Question

A 21.5L sample of gas at 107kPa has a temperature of 27.20C. What is the pressure of the gas if it is transferred to a 32.6L container at 44.10C?

Answer 1

`P_2 ~~ "74.5 kPa"`

Explanation:

Use

`PV=nRT`

where `n` and `R` stay constant during the transfer.

`nR=(PV)/(T)`

so

`[P_1V_1]/(T_1) = [P_2V_2]/(T_2)`

or

`P_2=[P_1V_1T_2]/(V_2T_1)`

Don't forget that

`T = θ+273.15`

So

`P_2 = ("107 kPa" * "21.5 L" * (44.10 + 273.15)\ "K")/("32.6 L" * (27.20 + 273.15) \ "K")`

`P_2 ~~ "74.5 kPa"`