How do you write an equation for a circle with center at (3, -6); radius = 5?
1 Answer
Aug 8, 2018
Explanation:
#"the equation of a circle in standard form is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where "(a,b)" are the coordinates of the centre and r"#
#"is the radius"#
#"here "(a,b)=(3,-6)" and "r=5#
#(x-3)^2+(y+6)^2=25larrcolor(red)" is equation of circle"#
