How do you solve #5r+3=2r^2#?
2 Answers
Aug 8, 2018
Explanation:
So
Aug 8, 2018
Explanation:
#"rearrange into standard form ";ax^2+bx+c=0;a!=0#
#"subtract "5r+3" from both sides"#
#2r^2-5r-3=0#
#"factor using the a-c method"#
#"the factors of the product "2xx-3=-6#
#"which sum to "-5" are "-6" and "+1#
#"split the middle term using these factors"#
#2r^2-6r+r-3=0larrcolor(blue)"factor by grouping"#
#color(red)(2r)(r-3)color(red)(+1)(r-3)=0#
#"take out the "color(blue)"common factor "(r-3)#
#(r-3)(color(red)(2r+1))=0#
#"equate each factor to zero and solve for r"#
#2r+1=0rArrr=-1/2#
#r-3=0rArrr=3#