How do you solve $4x^2=9x$ ?

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Answer 1 · 2016-05-28T18:06:18

$x = 0, 9/4$

$4x^2 = 9x$
$4x^2 - 9x = 0$
$x(4x-9)=0$
$x=0$
$4x-9=0$
$4x=9$
$x= 9/4$

Answer 2 · 2018-08-10T02:40:32

$x=0$ and $x=9/4$

We have a second degree term, so this is beginning to look like a quadratic. Let's subtract $9x$ from both sides to get

$4x^2-9x=0$

Both terms have an $x$ in them, so we can factor that out to get

$x(4x-9)=0$

Setting both factors equal to zero, we get

$x=0$ and $x=9/4$

Hope this helps!

How do you solve 4x^2=9x4x^2=9x?