How do you graph the circle with center at (-4, 2) and radius 5 and label the center and at least four points on the circle, then write the equation of the circle?
1 Answer
Aug 10, 2018
See explanation...
Explanation:
You are probably familiar with the fact that a triangle with sides of lengths
That means that all of the following integer points will be on the circle of radius
(-4, 2) +- (5, 0)" " i.e.(-9, 2) and(1, 2)
(-4, 2) +- (0, 5)" " i.e.(-4, -3) and(-4, 7)
(-4, 2) +- (3, 4)" " i.e.(-7, -2) and(-1, 6)
(-4, 2) +- (4, 3)" " i.e.(-8, -1) and(0, 5)
(-4, 2) +- (3, -4)" " i.e.(-7, 2) and(-1, -2)
(-4, 2) +- (4, -3)" " i.e.(-8, 5) and(0, -1)
The equation of a circle with centre
(x-h)^2+(y-k)^2 = r^2
So in our case, we can write:
(x+4)^2+(x-2)^2 = 25
graph{((x+4)^2+(y-2)^2 - 25)((x+4)^2+(y-2)^2 - 0.04) = 0 [-16.41, 6, -3.64, 7.2]}